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Are you able to solve this?
by Snowflakes - Wednesday September 13, 2023 at 02:38 PM
#1
"2C 28 2E 3A 1A 0C 18 08 1F 1E 0E 12"
#2
Mac address or fingerprint from pgp?

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#3
he presents himself this way: SELECT * FROM user WHERE login="amFvCg==" AND password="2C 28 2E 3A 1A 0C 18 08 1F 1E 0E 12"
#4
(Sep 13, 2023, 02:38 PM)Snowflakes Wrote: "2C 28 2E 3A 1A 0C 18 08 1F 1E 0E 12"

if you throw this in cyberchef and run it with magic and play with the depth you might find what you're looking for. For example I found this with Hex and XOR using
7b
as the key:

WSUAawcsdeui
#5
The last non-spam response in the topic was more than a month ago. I close the topic as irrelevant to prevent spam. If this is not the case, please send a pm and I will open the topic for discussion again.


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